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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: 1 / 3x – 2 – 4 / 3x + 2 – 10x +8 / 9x^2 – 4

Tháng Hai 26, 2023 Toán học 2 Comments 0 views

Toán Lớp 8: 1 / 3x – 2 – 4 / 3x + 2 – 10x +8 / 9x^2 – 4

Comments ( 2 )

  1. lanngocha
    lanngocha
    26 Tháng Hai, 2023 at 3:17 sáng
    Reply
    $\text{ @HV }$
    $\dfrac{1}{3x – 2}$ – $\dfrac{4}{3x + 2}$ – $\dfrac{10x + 8}{9x^2 – 4}$
    = $\dfrac{1}{3x – 2}$ – $\dfrac{4}{3x + 2}$ – $\dfrac{10x + 8}{(3x – 2).(3x + 2)}$
    = $\dfrac{3x + 2}{(3x – 2).(3x + 2)}$ – $\dfrac{12x – 8}{(3x – 2).(3x + 2)}$ – $\dfrac{10x + 8}{(3x – 2).(3x + 2)}$
    = $\dfrac{3x + 2 – 12x + 8 – 10x – 8}{(3x – 2).(3x + 2)}$
    = $\dfrac{-19x + 2}{(3x – 2).(3x + 2)}$
     

  2. daithanh
    daithanh
    26 Tháng Hai, 2023 at 3:17 sáng
    Reply
    Giải đáp:
    = {- 19x + 2}/{(3x – 2)(3x + 2)} 
    Lời giải và giải thích chi tiết:
     1/{3x – 2} – 4/{3x + 2} – {10x + 8}/{9x^2 – 4}        (ĐKXĐ: x ne +- 3/2)
    = 1/{3x – 2} – 4/{3x + 2} – {10x + 8}/{(3x)^2 – 2^2}
    = 1/{3x – 2} – 4/{3x + 2} – {10x + 8}/{(3x – 2)(3x + 2)}
    = {3x + 2}/{(3x – 2)(3x + 2)} – {4(3x – 2)}/{(3x – 2)(3x + 2)} – {10x + 8}/{(3x – 2)(3x + 2)}
    = {3x + 2}/{(3x – 2)(3x + 2)} – {12x – 8}/{(3x – 2)(3x + 2)} – {10x + 8}/{(3x – 2)(3x + 2)}
    = {3x + 2 – (12x – 8) – (10x + 8)}/{(3x – 2)(3x + 2)}
    = {3x + 2 – 12x + 8 – 10x – 8}/{(3x – 2)(3x + 2)}
    = {(3x – 12x – 10x) + (2 + 8 – 8)}/{(3x – 2)(3x + 2)}
    = {- 19x + 2}/{(3x – 2)(3x + 2)}
    #SunHee

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222-9+11+12:2*14+14 = ? ( )

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