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Toán Lớp 8: 1,x^3+x^2+x+1=0 2,x^2-4x+4=0 giúp mk vs

Home/ Toán Lớp 8: 1,x^3+x^2+x+1=0 2,x^2-4x+4=0 giúp mk vs

Toán Lớp 8: 1,x^3+x^2+x+1=0 2,x^2-4x+4=0 giúp mk vs

Madelyn Tháng Bảy 15, 2022 Toán học 2 Comments 0 views

Toán Lớp 8: 1,x^3+x^2+x+1=0
2,x^2-4x+4=0
giúp mk vs

Comments ( 2 )

tonhitruc
15 Tháng Bảy, 2022 at 4:10 sáng

Reply

x^3 + x^2 + x + 1 = 0

( x^3 + x^2 ) + ( x + 1 ) = 0

x^2( x + 1 ) + ( x + 1 ) = 0

( x^2 + 1 )( x + 1 ) = 0

=> \(\left[ \begin{array}{l}x^2+ 1 = 0\\x+1=0\end{array} \right.\)

=> \(\left[ \begin{array}{l}x^2=-1( Loại )\\x=-1\end{array} \right.\)

=> \(\left[ \begin{array}{l}x=…\\x=-1\end{array} \right.\)
thaolanphuobg
15 Tháng Bảy, 2022 at 4:10 sáng

Reply

x^3+x^2+x+1=0

<=>(x^3+x^2)+(x+1)=0

<=>x^2(x+1)+(x+1)=0

<=>(x^2+1)(x+1)=0

<=>\(\left[ \begin{array}{l}x^2+1=0\\x+1=0\end{array} \right.\)

<=>\(\left[ \begin{array}{l}x^2=-1 ( vô lí )\\x=-1\end{array} \right.\)

Vậy S = {-1 }

x^2-4x+4=0

<=>(x-2)^2=0

<=>x-2=0

<=>x=2

Vậy S={2}

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