Toán Lớp 8: 1/x^2-3x+2 ; 1/2x^2+3x-5
Quy đồng phân thức sau (ghi rõ cách làm)
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Toán Lớp 8: 1/x^2-3x+2 ; 1/2x^2+3x-5
Quy đồng phân thức sau (ghi rõ cách làm)
Comments ( 1 )
\dfrac{1}{{{x^2} – 3x + 2}} = \dfrac{1}{{{x^2} – 2x – x + 2}} = \dfrac{1}{{\left( {x – 1} \right)\left( {x – 2} \right)}}\\
\dfrac{1}{{2{x^2} + 3x – 5}} = \dfrac{1}{{2{x^2} + 5x – 2x – 5}} = \dfrac{1}{{\left( {2x + 5} \right)\left( {x – 1} \right)}}\\
MSC = \left( {x – 1} \right)\left( {x – 2} \right)\left( {2x + 5} \right)\\
+ )\dfrac{1}{{{x^2} – 3x + 2}} = \dfrac{{2x + 5}}{{\left( {x – 1} \right)\left( {x – 2} \right)\left( {2x + 5} \right)}}\\
+ )\dfrac{1}{{2{x^2} + 3x – 5}} = \dfrac{{x – 2}}{{\left( {x – 1} \right)\left( {x – 2} \right)\left( {2x + 5} \right)}}
\end{array}$