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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tính: 3 + 3^2 + 3^3 + – + 3^1000

Toán Lớp 7: Tính:
3 + 3^2 + 3^3 + …. + 3^1000

Comments ( 2 )

  1. Lời giải và giải thích chi tiết:
    Đặt  A = 3 + 3^2 + 3^3 + ……. + 3^1000
    3A = 3^2 + 3^3 + 3^4 + ………… + 3^1001
    3A – A = (3^2 + 3^3 + 3^4 + ………… + 3^1001) – (3 + 3^2 + 3^3 + ……. + 3^1000)
    2A = 3^1001 – 3
    A = (3^1001 – 3)/2
    => 3 + 3^2 + 3^3 + ……. + 3^1000 = (3^1001 – 3)/2

  2. 1+3^1+3^2+3^3+…………….+3^1000
    Đặt A=1+3^1+3^2+3^3+…………….+3^1000
    3A=3+3^2+3^3+3^4+….+3^1001
    3A-A=2A=(3+3^2+3^3+3^4+….+3^1001)-(1+3^1+3^2+3^3+…………….+3^1000)
    2A=3^1001-1
    A=$\frac{ 3^{1001}-1 }{2}$
     
     

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222-9+11+12:2*14+14 = ? ( )

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