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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tìm x,y,z biết x/2=y/3 ; y/5=z/7 và x+y+z=138

Toán Lớp 7: Tìm x,y,z biết
x/2=y/3 ; y/5=z/7 và x+y+z=138

Comments ( 2 )

  1. Theo bài ra, ta có:
    x/2=y/3
    $⇒\dfrac{x}{10}=\dfrac{y}{15}(1)$
    y/5=z/7
    $⇒\dfrac{y}{15}=\dfrac{z}{21}(2)$
    Từ $(1),(2)⇒\dfrac{x}{10}=\dfrac{y}{15}=\dfrac{z}{21}$
    Áp dụng …
    $\dfrac{x}{10}=\dfrac{y}{15}=\dfrac{z}{21}=\dfrac{x+y+z}{10+15+21}=\dfrac{138}{46}=3$
    $\dfrac{x}{10}=3⇒x=3.10=30$
    $\dfrac{y}{15}=3⇒y=3.15=45$
    $\dfrac{z}{21}=3⇒z=3.21=63$

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222-9+11+12:2*14+14 = ? ( )