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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tìm x, biết a, $\frac{x-2}{33}$ = $\frac{-297}{2-x}$ b, $\frac{5}{12}$ √x – $\frac{1}{6}$ = $\frac{1}{3}$ c, |x+1|- 2x = 7 d, |x-1|+|2+

Tháng Sáu 14, 2022 Toán học 1 Comment 0 views

Toán Lớp 7: Tìm x, biết
a, $\frac{x-2}{33}$ = $\frac{-297}{2-x}$
b, $\frac{5}{12}$ √x – $\frac{1}{6}$ = $\frac{1}{3}$
c, |x+1|- 2x = 7
d, |x-1|+|2+x| = 1
e, 3($\frac{x}{3}$ + 1)$^{2}$ – $\frac{3}{8}$ = $\frac{21}{16}$

Comments ( 1 )

  1. chauhoangmy98
    chauhoangmy98
    14 Tháng Sáu, 2022 at 6:45 chiều
    Reply
    a) ⇔ (x – 2)(2 – x) = -297 . 33 ⇔ $-x^{2}$ + 4x – 4 = -9801 ⇔ $x^{2}$ – 4x + 4 = 9801 ⇔ $x^{2}$ – 4x – 9797 = 0 ⇔ $x^{2}$ – 101x + 97x – 9797 = 0 ⇔ (x – 101)(x + 97) = 0 ⇔\(\left[ \begin{array}{l}x=101\\x=-97\end{array} \right.\) 
    b) ⇔ $\frac{5}{12}$ √x = $\frac{1}{2}$ ⇔ √x = $\frac{6}{5}$ ⇔ x = $\frac{36}{25}$ 
    c) ⇔ x + 1 = 7 + 2x ⇔ x = -6
        ⇔ x + 1 = -7 – 2x ⇔ 3x = -8 ⇔ x = $\frac{-8}{3}$ 
    e) 3(

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222-9+11+12:2*14+14 = ? ( )

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