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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: tìm x a) 2,8 : 0,5 = |x-1| : 1,5 b) 2( x – 1/2 ) – 5( x + 1/3 ) = -x + 1/3 c) |x – 5/6| + 7/2 = 5 d) 7|x| – 339/14 = |-53/14| giúp mì

Toán Lớp 7: tìm x
a) 2,8 : 0,5 = |x-1| : 1,5
b) 2( x – 1/2 ) – 5( x + 1/3 ) = -x + 1/3
c) |x – 5/6| + 7/2 = 5
d) 7|x| – 339/14 = |-53/14|
giúp mình zới

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
    a) 2,8:0,5=|x-1|:1,5
    <=> 5,6 = |x-1| : 1,5
    <=> |x-1|=5,6 . 1,5
    <=> x-1 = 8,4
    <=> \(\left[ \begin{array}{l}x-1=8,4\\x-1=-8,4\end{array} \right.\) 
    <=> \(\left[ \begin{array}{l}x=9,4\\x=-7,4\end{array} \right.\) 
    b) 2(x-1/2)-5(x+1/3)=-x+1/3
    <=> 2x – 1-5x – 5/3 = -x + 1/3
    <=> -3x +x = 1/3 + 5/3 +1
    <=> -2x = 3
    <=> x = -3/2
    c)|x-5/6| +7/2 = 5
    <=> |x-5/6|=5-7/2
    <=> |x-5/6|=(10)/2-7/2
    <=> |x-5/6|=3/2
    <=>\(\left[ \begin{array}{l}x-\dfrac{5}{6}=\dfrac{3}{2}\\x-\dfrac{5}{6}=-\dfrac{3}{2}\end{array} \right.\) 
    <=>\(\left[ \begin{array}{l}x=\dfrac{7}{3}\\x=-\dfrac{2}{3}\end{array} \right.\) 
    d) 7|x|-(339)/(14)=|-(53)/(14)|
    <=> 7|x|-(339)/(14)=(53)/(14)
    <=> 7|x| =(53)/(14)+(339)/(14)
    <=> 7|x| =28
    <=> |x| = 4
    <=>\(\left[ \begin{array}{l}x=4\\x=-4\end{array} \right.\) 

  2. Giải đáp:
    a, 2,8 : 0,5 = |x-1| : 1,5
    => |x-1| : 1,5 =5,6
    => |x-1| = 8,4
    @ TH1 : x-1 = 8,4
    -> x = 9,4
    @TH2 : x-1 = -8,4
    -> x = -7,4
    Vậy x ∈ {9,4 ; -7,4}
    b,  2( x – 1/2 ) – 5( x + 1/3 ) = -x + 1/3
    => 2x – 1 – 5x – 5/3 = -x + 1/3
    => 2x – 5x – 8/3 = -x + 1/3
    => -3x = -x + 3
    -> -3x + x = 3
    -> -2x = 3
    -> x = -3/2
    Vậy x = -3/2
    c, |x – 5/6| + 7/2 = 5
    => |x-5/6| = 3/2
    @ TH1 : x-5/6 = 3/2
    -> x = 7/3
    @TH2 : x-5/6 = -3/2
    -> x = -2/3
    Vậy x ∈ {7/3 ; -2/3}
    d, 7|x| – 339/14 = |-53/14|
    7.|x| – 339/14 = 53/14
    -> 7.|x| = 28
    -> |x| = 4
    -> x = ±4
    Vậy x = ±4
     

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222-9+11+12:2*14+14 = ? ( )

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