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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Tam giác ABC có, góc B = góc C, góc A = 89 độ. Góc B bằng:

Toán Lớp 7: Tam giác ABC có, góc B = góc C, góc A = 89 độ. Góc B bằng:

Comments ( 2 )

  1. Ta có:
    hat\{A} + hat\{B} + hat\{C} = 180^o (tổng 3 góc của tam giác)
    => 89^o + 2 hat\{B} = 180^o
    => 2 hat\{B} = 180^o – 89^o
    => 2 hat\{B} = 91^o
    => hat\{B} = 91^0 : 2
    => hat\{B} = 45,5^o
    Vậy hat\{B} = 45,5^o
     

  2. $\textit{Giải đáp+Lời giải và giải thích chi tiết:}$
    $\ Δ ABC$=$\widehat{BAC}$+$\widehat{ABC}$+$\widehat{ACB}$=$180^o$
    -> $\widehat{ACB}$+$\widehat{ABC}$+$89^o$=$180^o$
    -> 2·$\widehat{ABC}$=$180^o$-$89^o$
    -> 2·$\widehat{ABC}$=$91^o$
    -> $\widehat{ABC}$=$91^o$÷2
    -> $\widehat{ABC}$=$45,5^o$
    Vậy $\widehat{ABC}$=$\widehat{ACB}$=$45,5^o$
     

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222-9+11+12:2*14+14 = ? ( )