Toán Lớp 7: giúp vs ạ, em đang cần gấp
tìm x
(x+4).(2-3x)=0
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Toán Lớp 7: giúp vs ạ, em đang cần gấp
tìm x
(x+4).(2-3x)=0
Comments ( 2 )
(x+4)(2-3x)=0
\(⇔\left[ \begin{array}{l}x+4=0\\2-3x=0\end{array} \right.\)
\(⇔\left[ \begin{array}{l}x=-4\\x=\frac{2}{3}\end{array} \right.\)
Vậy x=-4 hoặc x=2/3
$\left(x+4\right)\left(2-3x\right)=0$
$⇒x+4=0\quad \mathrm{hoặc}\quad \:2-3x=0$
TH1: $x+4=0$
$⇒x+4-4=0-4$
$⇒x=-4$
TH2: $2-3x=0$
$⇒2-3x-2=0-2$
$⇒-3x=-2$
$⇒\dfrac{-3x}{-3}=\dfrac{-2}{-3}$
$⇒x=\dfrac{2}{3}$
$\text{Vậy x $\in$ {-4 ; $\dfrac{2}{3}$}}$