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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: [($\frac{-1}{3}$)$^{2}$ . $\frac{27}{7}$ + $\sqrt{\frac{4}{49}}$ – `3`] : $\frac{4}{7}$

Toán Lớp 7: [($\frac{-1}{3}$)$^{2}$ . $\frac{27}{7}$ + $\sqrt{\frac{4}{49}}$ – 3] : $\frac{4}{7}$

Comments ( 2 )

  1. [((-1)/3)^2 . 27/7+sqrt(4/49) -3]:4/7 
    =(1/9 . 27/7+2/7-3):4/7 
    =(3/7+2/7-3):4/7
    =(5/7-3):4/7
    =(-16)/7:4/7
    =(-16)/7 . 7/4
    =-4

  2. Giải đáp:
    $-4$
    Lời giải và giải thích chi tiết:
    $\left[\left(\dfrac{-1}{3}\right)^{\large 2}\cdot\dfrac{27}{7}+\sqrt{\dfrac{4}{49}}-3\right]:\dfrac47\\=\left(\dfrac19\cdot\dfrac{27}{7}+\dfrac27-3\right):\dfrac47\\=\left(\dfrac37+\dfrac27-3\right):\dfrac47\\=\left(\dfrac57-3\right):\dfrac47\\=\dfrac{-16}{7}:\dfrac47\\=-4$

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222-9+11+12:2*14+14 = ? ( )