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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Cho hàm số y=f(x)=x mũ 2 + 5 a) Tính f(2); f(-1/3) b) Tìm x để f(x) = x+5

Toán Lớp 7: Cho hàm số y=f(x)=x mũ 2 + 5
a) Tính f(2); f(-1/3)
b) Tìm x để f(x) = x+5

Comments ( 2 )

  1. Answer
    $\text{a, Ta có:}$ y = f(x) = x^2 + 5
    $\text{Vói}$ f(2)
    => 2^2 + 5
    = 4 + 5
    = 9
    $\text{Với}$ f(-1/3)
    => (-1/3)^{2} + 5
    = 1/9 + 5
    = 46/9
    ______________________
    $\text{b, Ta có}$ y = f(x) = x^2 + 5
    => x^2 + 5 = x + 5
    => x^2 + 5 – x – 5 = 0
    => x^2 – x + 5 – 5 = 0
    => x^2 – x = 0
    => x . (x – 1) = 0
    => $\left[\begin{matrix} x = 0\\ x – 1 = 0\end{matrix}\right.$
    => $\left[\begin{matrix} x = 0\\ x = 0 + 1\end{matrix}\right.$
    => $\left[\begin{matrix} x = 0\\ x = 1\end{matrix}\right.$
    $\text{Vậy}$ x \in {0 ; 1}

  2. $\text{a) Ta có:}$
         $f(x)=x^2+5$
    ⇒ $f(2)=2^2+5=9$
    ⇒ $f\left(-\dfrac{1}{3}\right)=\left(-\dfrac{1}{3}\right)^2+5=\dfrac{46}{9}$
    $\text{}$
    $\text{b) Ta có:}$
         $f(x)=x+5$
    ⇔ $x^2+5=x+5$
    ⇔ $x^2-x=0$
    ⇔ $x(x-1)=0$
    ⇔ $\left[\begin{array}{l}x=0\\x-1=0\end{array}\right.$
    ⇔ $\left[\begin{array}{l}x=0\\x=1\end{array}\right.$

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222-9+11+12:2*14+14 = ? ( )