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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: cho a ²=a.c ; c ²=b.d chứng minh a ³+b ³ – c ³/b ³+c ³ -d ³ =(2a+3b -5c)/(2b +3b -5d)

Toán Lớp 7: cho a ²=a.c ; c ²=b.d chứng minh a ³+b ³ – c ³/b ³+c ³ -d ³ =(2a+3b -5c)/(2b +3b -5d)

Comments ( 2 )

  1. \text{Theo đề bài ta có:} $\\$ a^2 =a.a $\\$ => a= c $\\$ => a^2= c^2 $\\$ => a^2=ac=c^2=bd $\\$ \text{Áp dụng tính chất dãy tỉ số bằng nhau, ta có:} $\\$ \frac{a^3 + b^3 – c^3}{b^3 + c^3 – d^3}= \frac{a^3}{b^3}=\frac{b^3}{c^3}=\frac{c^3}{d^3} $\\$ \text{Ta lấy:} \frac{b^3}{c^3}=\frac{c^3}{d^3}$\\$ b^3 . d^3=c^.c^3$\\$ \frac{b^3}{c^3}=\frac{d^3}{c^3} = \frac{c^3}{c^3}=\frac{d^3}{b^3}$\\$ 1=\frac{d^3}{b^3}$\\$ => \frac{a^3 + b^3 – c^3}{b^3 + c^3 – d^3}= \frac{a^3}{b^3}=\frac{b^3}{c^3}=\frac{c^3}{d^3} = 1 \frac{2a + 3b – 5c}{2b + 3b – 5d}=\frac{2a}{2b}=\frac{3b}{3b}=\frac{5c}{5d}$\\$ \frac{2a}{2b}=1=\frac{5c}{5d}$\\$ =>\frac{2a + 3b – 5c}{2b + 3b – 5d}=\frac{2a}{2b}=\frac{3b}{3b}=\frac{5c}{5d}=1$\\$ \text{Vì:} 1=1$\\$ \text{Vậy:} \frac{a^3 + b^3 – c^3}{b^3 + c^3 – d^3}=\frac{2a + 3b – 5c}{2b + 3b – 5d}\text{(đpcm)}
     

  2. Theo đề bài ta có:
    a
    2
    =
    a
    .
    a

    a
    =
    c

    a
    2
    =
    c
    2

    a
    2
    =
    a
    c
    =
    c
    2
    =
    b
    d
    Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
    a
    3
    +
    b
    3

    c
    3
    b
    3
    +
    c
    3

    d
    3
    =
    a
    3
    b
    3
    =
    b
    3
    c
    3
    =
    c
    3
    d
    3
    Ta lấy:

    b
    3
    c
    3
    =
    c
    3
    d
    3
    b
    3
    .
    d
    3
    =
    c
    .
    c
    3
    b
    3
    c
    3
    =
    d
    3
    c
    3
    =
    c
    3
    c
    3
    =
    d
    3
    b
    3
    1
    =
    d
    3
    b
    3

    a
    3
    +
    b
    3

    c
    3
    b
    3
    +
    c
    3

    d
    3
    =
    a
    3
    b
    3
    =
    b
    3
    c
    3
    =
    c
    3
    d
    3
    =
    1
    2
    a
    +
    3
    b

    5
    c
    2
    b
    +
    3
    b

    5
    d
    =
    2
    a
    2
    b
    =
    3
    b
    3
    b
    =
    5
    c
    5
    d
    2
    a
    2
    b
    =
    1
    =
    5
    c
    5
    d

    2
    a
    +
    3
    b

    5
    c
    2
    b
    +
    3
    b

    5
    d
    =
    2
    a
    2
    b
    =
    3
    b
    3
    b
    =
    5
    c
    5
    d
    =
    1
    Vì:

    1
    =
    1
    Vậy:
    a
    3
    +
    b
    3

    c
    3
    b
    3
    +
    c
    3

    d
    3
    =
    2
    a
    +
    3
    b

    5
    c
    2
    b
    +
    3
    b

    5
    d
    (đpcm)

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222-9+11+12:2*14+14 = ? ( )

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