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Toán Lớp 7: Bài 1 $x^{2}$ + ( y – $\frac{1}{10}$ ) =0 ($\frac{1}{2}$x-5)$^{20}$ + ( $y^{2}$ – $\frac{1}{4}$ )$^{10}$ $\leq$0

Home/ Toán Lớp 7: Bài 1 $x^{2}$ + ( y – $\frac{1}{10}$ ) =0 ($\frac{1}{2}$x-5)$^{20}$ + ( $y^{2}$ – $\frac{1}{4}$ )$^{10}$ $\leq$0

Toán Lớp 7: Bài 1 $x^{2}$ + ( y – $\frac{1}{10}$ ) =0 ($\frac{1}{2}$x-5)$^{20}$ + ( $y^{2}$ – $\frac{1}{4}$ )$^{10}$ $\leq$0

Thanh Thu Tháng Tám 18, 2022 Toán học 1 Comment 0 views

Toán Lớp 7: Bài 1
$x^{2}$ + ( y – $\frac{1}{10}$ ) =0
($\frac{1}{2}$x-5)$^{20}$ + ( $y^{2}$ – $\frac{1}{4}$ )$^{10}$ $\leq$0

Comments ( 1 )

hongocha12
18 Tháng Tám, 2022 at 4:54 chiều

Reply

Giải đáp:

Sửa đề câu a)

x^2+(y-1/10)^4=0

a)

Với mọi x thuộc R: \(x^2\ge0;\left(y-\dfrac{1}{10}\right)^4\ge0\Leftrightarrow x^2+\left(y-\dfrac{1}{10}\right)^4\ge0\)

\(“=”\Leftrightarrow\left\{{}\begin{matrix}x=0\\y=\dfrac{1}{10}\end{matrix}\right.\)

b)

\(\left(\dfrac{1}{2}x-5\right)^{20}+\left(y^2-\dfrac{1}{4}\right)^{10}\ge0\forall x\in R\)

*Mà: \(\left(\dfrac{1}{2}x-5\right)^{20}+\left(y^2-\dfrac{1}{4}\right)^{10}\le0\)

*Xảy ra khi: \(\left\{{}\begin{matrix}x=10\\y=\pm\dfrac{1}{2}\end{matrix}\right.\)

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