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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: a) (3x-1/5)^200+(2/5y+4/7)^1968=0 b) (4/7x-1)^2+(-2/3y+4)^68≤0 GIÚP MIK VỚI CÁC BẠN ƠI! CẦN GẤP Ai nhanh mik vote 5*

Toán Lớp 7: a) (3x-1/5)^200+(2/5y+4/7)^1968=0
b) (4/7x-1)^2+(-2/3y+4)^68≤0
GIÚP MIK VỚI CÁC BẠN ƠI!
CẦN GẤP
Ai nhanh mik vote 5*

Comments ( 1 )

  1. $\\$
    a,
    (3x-1/5)^{200}+(2/5y + 4/7)^{1968}=0
    Vì (3x-1/5)^{200} ≥0∀x, (2/5 y+4/7)^{1968} ≥0∀y
    -> (3x-1/5)^{200}+(2/5y + 4/7)^{1968} ≥0∀x,y
    Dấu “=” xảy ra khi :
    (3x-1/5)^{200}=0, (2/5y + 4/7)^{1968}=0
    ↔ 3x-1/5=0, 2/5 y+4/7=0
    ↔ x=1/15,y=(-10)/7
    Vậy (x;y)=(1/15; (-10)/7)
    $\\$
    b,
    (4/7 x-1)^2 +( (-2)/3 y+4)^{68} ≤0
    Vì (4/7 x-1)^2 ≥0∀x,((-2)/3 y+4)^{68} ≥0∀y
    ->(4/7 x-1)^2+((-2)/3 y+4)^{68} ≥0∀x,y
    Dấu “=” xảy ra khi :
    (4/7 x-1)^2=0,((-2)/3 y+4)^{68}=0
    ↔ 4/7 x-1=0, (-2)/3 y+4=0
    ↔x=7/4, y=6
    Vậy (x;y)=(7/4;6)
     

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222-9+11+12:2*14+14 = ? ( )

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