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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: 3(x-1)=2(y-2);4(y-2)=3(z-3) và 2x+3y-z=50

Toán Lớp 7: 3(x-1)=2(y-2);4(y-2)=3(z-3) và 2x+3y-z=50

Comments ( 2 )

  1. 3( x – 1 ) = 2( y – 2 )
    6( x – 1 ) = 4( y – 2 )
    mà 4( y – 2 ) = 3( z – 3 )
    $\Rightarrow$ 6( x – 1 ) = 4( y – 2 ) = 3( z – 3 )
    $\Rightarrow$ $\dfrac{6( x – 1 )}{12}$ = $\dfrac{4( y – 2 )}{12}$ = $\dfrac{3( z – 3 )}{12}$
    $\Rightarrow$ $\dfrac{x – 1}{2}$ = $\dfrac{y – 2}{3}$ = $\dfrac{z – 3}{4}$
                              Áp dụng t/c DTSBN, ta có :
     $\dfrac{x – 1}{2}$ = $\dfrac{y – 2}{3}$ = $\dfrac{z – 3}{4}$ = $\dfrac{2x – 2}{4}$ = $\dfrac{3y – 6}{9}$ =  $\dfrac{2x – 2 + 3y – 6 – z}{9}$ = $\dfrac{( 2x + 3y – z ) – ( 2 + 6 )}{9}$ = $\dfrac{14}{3}$
    $\Rightarrow$ $\begin{cases} x = \dfrac{31}{3}\\y = 16\\z = \dfrac{68}{3}\end{cases}$
                           Vậy x = $\dfrac{31}{3}$ ; y = 16 ; z = $\dfrac{68}{3}$

  2. $\text{ 3( x – 1 ) = 2( y – 2 ) }$
    $\Rightarrow$ $\text{ 6( x – 1 ) = 4( y – 2 ) }$
    $\text{ mà 4( y – 2 ) = 3( z – 3 ) }$
    $\Rightarrow$ $\text{ 6( x – 1 ) = 4( y – 2 ) = 3( z – 3 ) }$
    $\Rightarrow$ $\text{ $\dfrac{6( x – 1 )}{12}$ = $\dfrac{4( y – 2 )}{12}$ = $\dfrac{3( z – 3 )}{12}$ }$
    $\Rightarrow$ $\text{ $\dfrac{x – 1}{2}$ = $\dfrac{y – 2}{3}$ = $\dfrac{z – 3}{4}$ }$
                            $\text{ Áp dụng tính chất dãy tỉ số bằng nhau, ta có : }$
     $\dfrac{x – 1}{2}$ = $\dfrac{y – 2}{3}$ = $\dfrac{z – 3}{4}$ = $\dfrac{2x – 2}{4}$ = $\dfrac{3y – 6}{9}$ = $\dfrac{( 2x – 2 ) + ( 3y – 6 ) – z }{4 + 9 – 4}$ = $\dfrac{2x – 2 + 3y – 6 – z}{9}$ = $\dfrac{( 2x + 3y – z ) – ( 2 + 6 )}{9}$ = $\dfrac{50 – 8}{9}$ = $\dfrac{14}{3}$
    $\Rightarrow$ $\begin{cases} x -1 = \dfrac{14}{3}. 2 = \dfrac{28}{3}\\y – 2 = \dfrac{14}{3}. 3 = 14\\z – 3 = \dfrac{14}{3}. 4 = \dfrac{56}{3}\end{cases}$    $\Rightarrow$ $\begin{cases} x = \dfrac{31}{3}\\y = 16\\z = \dfrac{68}{3}\end{cases}$
                          $Vậy$ ( $x$ ; $y$ ; $z$ ) $=$ ( $\dfrac{31}{3}$ ; $16$ ; $\dfrac{68}{3}$ }

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222-9+11+12:2*14+14 = ? ( )

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