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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: `1,` `S = ` 2 + $2^2$ + $2^3$ + $2^4$ + … + $2^{99}$ + $2^{100}$ Tính `S`

Toán Lớp 7: 1, S = 2 + $2^2$ + $2^3$ + $2^4$ + … + $2^{99}$ + $2^{100}$
Tính S

Comments ( 2 )

  1. Giải đáp:
     
    Lời giải và giải thích chi tiết:
    S=2+$2^{2}$+ $2^{3}$ +$2^{4}$ …+$2^{99}$+ $2^{100}$ 
    2S=$2^{2}$+ $2^{3}$ +$2^{4}$ …+$2^{99}$+ $2^{100}$ +$2^{101}$
    2S-S=($2^{2}$+ $2^{3}$ +$2^{4}$ …+$2^{99}$+ $2^{100}$ +$2^{101}$)-(2+$2^{2}$+ $2^{3}$ +$2^{4}$ …+$2^{99}$+ $2^{100}$ )
    S=$2^{101}$-2 

  2. Giải đáp:
    $\text{S = $2^{101}$ – 2}$ $\\$
    Lời giải và giải thích chi tiết: $\\$
    $\text{S = $2^{}$ + $2^{2}$ + $2^{3}$ + $2^{4}$ + … + $2^{99}$ + $2^{100}$}$ $\\$ $\text{2S = $2^{2}$ + $2^{3}$ + $2^{4}$ + … + $2^{99}$ + $2^{101}$}$ $\\$ $\text{2S – S = ($2^{2}$ + $2^{3}$ +  … + $2^{99}$ + $2^{101}$) – ($2^{}$ + $2^{2}$ + $2^{3}$ + … + $2^{99}$ + $2^{100}$)}$ $\\$ $\text{S = $2^{101}$ – 2}$

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222-9+11+12:2*14+14 = ? ( )