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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm số nguyên n sao cho, 3n+4 chia hết cho n+1

Toán Lớp 6: Tìm số nguyên n sao cho, 3n+4 chia hết cho n+1

Comments ( 2 )

  1. Để 3n+4 \vdots n+1
    ⇔ 3.(n+1)+1 \vdots n+1
    ⇔ 1 \vdots n+1
    ⇔n+1 ∈ Ư(1)={ 1 ; -1 }
    Lập bảng:
    \begin{array}{|c|c|c|}\hline \text{n}&\text{1}&\text{-1}\\\hline \text{n+1}&\text{0}&\text{-2}\\\hline \end{array}
    Vậy n ∈ { 0 ; -2 }
    #Huy

  2. 3n + 4 \vdots n + 1
    -> 3n + 4 – 3 . (n + 1) \vdots n + 1
    -> 3n + 4 – (3n + 3) \vdots n + 1
    -> 3n + 4 – 3n – 3 \vdots n + 1
    -> 4 – 3 \vdots n + 1
    -> 1 \vdots n + 1
    -> n + 1 ∈ Ư(1)
    -> n + 1 ∈ {1 ; -1}
    -> n ∈ {0 ; -2}
    Vậy n ∈ {0 ; -2}

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222-9+11+12:2*14+14 = ? ( )

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