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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: tìm số dư trong các phép chia 2017^2000 chia cho 3;5;6

Toán Lớp 6: tìm số dư trong các phép chia 2017^2000 chia cho 3;5;6

Comments ( 1 )

  1. 2017≡1(mod 3)
    ⇒$2017^{2000}$  ≡ $1^{2000}$ ≡ 1 (mod 3)
    ⇒ $2017^{2000}$ chia 3 dư 1
    $2017^{4}$ = ……….1 ≡ 1 (mod 5)
    ⇔$(2017^{4})^{500}$  ≡ $1^{500}$  ≡ 1 (mod 5)
    ⇒$2017^{2000}$ chia 5 dư 1
    2017≡1 (mod 6)
    ⇒$2017^{2000}$ ≡ $1^{2000}$ ≡ 1 (mod 6)
    ⇒ $2017^{2000}$ chia 6 dư 1
    Vậy $2017^{2000}$ chia 3,5,6 dư 1

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222-9+11+12:2*14+14 = ? ( )