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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: tìm n 15 chia hết cho ( 2n +1)

Toán Lớp 6: tìm n 15 chia hết cho ( 2n +1)

Comments ( 2 )

  1. Giải đáp:
     15 chia hết cho 2n+1
    =>2n+1 € Ư(15)={±1;±3;±5;±15}
    => 2n € {-2; 0; -4; 2; -6; 4; -16; 14}
    => n €{-1; 0; -2; 1; -3; 2; -8; 7}
    Vì  n€N => n€{0;1;2;7}
    Vậy n€{ 0; 1;2; 7}

  2. Ta có : 15 vdots 2n+1
    => 2n+1 ∈ Ư(15)
    Ư(15) = {1;3;5;15}
    2n+1 = {1;3;5;15}
    => n = { 0 ; 1 ; 2 ; 7}
     

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222-9+11+12:2*14+14 = ? ( )

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