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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm x biết : a) |x + 1,3| = 3,3 b) |2x – 5|= |x – 1| c) |5x – 7|/ x – 1 = 3 d) |x – 5|-|2x – 1|= 0 e) |x – 5|= 2x – 1

Toán Lớp 6: Tìm x biết :
a) |x + 1,3| = 3,3
b) |2x – 5|= |x – 1|
c) |5x – 7|/ x – 1 = 3
d) |x – 5|-|2x – 1|= 0
e) |x – 5|= 2x – 1

Comments ( 1 )

  1. text{Giải đáp + Lời giải và giải thích chi tiết}
     $a)$
    |x+1,3|=3,3
    =>\(\left[ \begin{array}{l}x+1,3=3,3\\x+1,3=-3,3\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=3,3-1,3\\x=-3,3-1,3\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=2\\x=-4,6\end{array} \right.\) 
    Vậy \(\left[ \begin{array}{l}x=2\\x=-4,6\end{array} \right.\) 
    $b)$
    |2x-5|=|x-1|
    =>\(\left[ \begin{array}{l}2x-5=x-1\\2x-5=1-x\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=4\\3x=6\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=4\\x=2\end{array} \right.\) 
    Vậy \(\left[ \begin{array}{l}x=4\\x=2\end{array} \right.\) 
    $c)$
    (|5x-7|)/(x-1)=3
    =>|5x-7|=3.(x-1)
    =>|5x-7|=3x-3
    text{Điều kiện: 3x-3≥0⇒x≥1}
    \(\left[ \begin{array}{l}5x-7=3x-3\\5x-7=3-3x\end{array} \right.\)
    =>\(\left[ \begin{array}{l}2x=4\\8x=10\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=2\\x=5/4\end{array} \right.\) 
    Vậy \(\left[ \begin{array}{l}x=2\\x=5/4\end{array} \right.\) 
    $d)$
    |x-5|-|2x-1|=0
    =>|x-5|=|2x-1|
    =>\(\left[ \begin{array}{l}x-5=2x-1\\x-5=1-2x\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}-x=4\\3x=6\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=-4\\x=2\end{array} \right.\) 
    Vậy \(\left[ \begin{array}{l}x=-4\\x=2\end{array} \right.\) 
    $e)$
    |x-5|=2x-1
    text{Điều kiện: 2x-1≥0⇒x≥1/2}
    \(\left[ \begin{array}{l}x-5=2x-1\\x-5=1-2x\end{array} \right.\)
    =>\(\left[ \begin{array}{l}-x=4\\3x=6\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=-4(loại)\\x=2\end{array} \right.\) 
    Vậy x=2
    xin hay nhất.

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222-9+11+12:2*14+14 = ? ( )