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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm x, biết: x^5 – 4x^3 = 0 help me, nê gờ

Toán Lớp 6: Tìm x, biết:
x^5 – 4x^3 = 0
help me, nê gờ

Comments ( 2 )

  1. x^5 – 4x^3 = 0
    x^3(x^2-4)=0
    => \(\left[ \begin{array}{l}x^3=0\\x^2-4=0\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=0\\x^2=4\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=0\\x^2=(±2)^2\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=0\\x^2=±2\end{array} \right.\) 
    Vậy x=0 hoặc x=±2

  2. x^5-4x^3=0          
    <=>x^3(x^2-4)=0                       
     <=>   \(\left[ \begin{array}{l}x^3=0\\x^2-4=0\end{array} \right.\) <=> \(\left[ \begin{array}{l}x=0\\x^2=4\end{array} \right.\) <=> \(\left[ \begin{array}{l}x=0\\x^2=(±2)^2\end{array} \right.\) <=> \(\left[ \begin{array}{l}x=0\\x=± 2\end{array} \right.\) 
    vậy x in {0;2;-2}          

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222-9+11+12:2*14+14 = ? ( )

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