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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm x a) 95-5.(2x-8)=45 b) 130-10(x+1)=55 c) 155-10(x+1)=55 d) 5(x+12)+22=92 e) (3x-2016)(5x-2020)=0 f) 1+3+5+-..+x=36 e) 1+2+-..

Toán Lớp 6: Tìm x
a) 95-5.(2x-8)=45
b) 130-10(x+1)=55
c) 155-10(x+1)=55
d) 5(x+12)+22=92
e) (3x-2016)(5x-2020)=0
f) 1+3+5+……+x=36
e) 1+2+……+x=45
Cý: dấu . là dấu nhân
2x là 2 . x

Comments ( 2 )

  1. a, 95-5.(2x-8)=45
    ↔5(2x-8)=95-45
    ↔5(2x-8)=50
    ↔2x-8=50:5
    ↔2x-8=10
    ↔2x=10+8
    ↔2x=18
    ↔x=18:2
    ↔x=9
    Vậy x=9
    b, 130-10(x+1)=55
    ↔10(x+1)=130-55
    ↔10(x+1)=75
    ↔x+1=75:10
    ↔x+1=7,5
    ↔x=7,5-1
    ↔x=6,5
    Vậy x=6,5
    c, 155-10(x+1)=55
    ↔10(x+1)=155-55
    ↔10(x+1)=100
    ↔x+1=100:10
    ↔x+1=10
    ↔x=10-1
    ↔x=9
    Vậy x=9
    d, 5(x+12)+22=92
    ↔5(x+12)=92-22
    ↔5(x+12)=70
    ↔x+12=70:5
    ↔x+12=14
    ↔x=14-12
    ↔x=2
    Vậy x=2
    e, (3x-2016)(5x-2020)=0
    @ Trường hợp 1:
    3x-2016=0
    ↔3x=2016
    ↔x=2016:3
    ↔x=672
    @ Trường hợp 2:
    5x-2020=0
    ↔5x=2020
    ↔x=2020:5
    ↔x=404
    Vậy x\in{672;404}
    f, 1+3+5+…+x=36(x>=0;)
    ↔{(x+1).[(x-1):2+1]}/{2}=36
    ↔(x+1).[(x-1):2+1]=36.2
    ↔(x+1).[(x-1):2+1]=72
    ↔(x+1).((x-1)/2+2/2)=72
    ↔(x+1).((x+1)/2)=72
    ↔((x+1)^2)/2=72
    ↔(x+1)^2=72.2
    ↔(x+1)^2=144
    ↔(x+1)^2=12^2( do x>=0 )
    ↔x+1=12 
    ↔x=12-1
    ↔x=11
    Vậy x=11
    e, 1+2+…+x=45(x>=0)
    ↔{x(x+1)}/{2}=45
    ↔x(x+1)=45.2
    ↔x(x+1)=90
    ↔x(x+10)=9.10( do x>=0 )
    ↔x=9
    Vậy x=9

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222-9+11+12:2*14+14 = ? ( )