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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm x : ( x + 3 )^2 = ( x + 3 )^5

Toán Lớp 6: Tìm x :
( x + 3 )^2 = ( x + 3 )^5

Comments ( 2 )

  1. giải thích các bước :
    (x+3)^2=(x+3)^5
    ↔️(x+3)^2-(x+3)^5=0
    ↔️(x+3)^2-(x+3)^2 . (X+3)^3=0
    ↔️(x+3)^2 [1-(x+3)^3]=0
    TH1: (x+3)^2=0
    ↔️x+3=0
    ↔️x=-3
    TH2: 1-(x+3)^3=0
    ↔️(x+3)^3=1
    ↔️x+3=1
    ↔️x=‐2
    Vậy x={-3;-2}

  2. Giải đáp:
    x\in{-3;-2}
    Trình bày lời giải:
     ( x + 3 )^2 = ( x + 3 )^5
    =>(x+3)^2-(x+3)^5=0
    =>(x+3)^2 . 1-(x+3)^2 . (x+3)^3=0 
    =>(x+3)^2 .[1-(x+3)^3]=0
    =>[((x+3)^2=0),(1-(x+3)^3=0):}
    =>[(x+3=0),((x+3)^3=1-0=1):}
    =>[(x=0-3=-3),(x+3=1):}
    =>[(x=-3),(x=-2):}
    Vậy x\in{-3;-2}

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222-9+11+12:2*14+14 = ? ( )

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