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Toán Lớp 6: S = 2 + $2^{2}$ + $2^{3}$ + $2^{4}$ + … + $2^{98}$ + $2^{99}$ + $2^{100}$

Home/ Toán Lớp 6: S = 2 + $2^{2}$ + $2^{3}$ + $2^{4}$ + … + $2^{98}$ + $2^{99}$ + $2^{100}$

Toán Lớp 6: S = 2 + $2^{2}$ + $2^{3}$ + $2^{4}$ + … + $2^{98}$ + $2^{99}$ + $2^{100}$

Phương Diễm Tháng Năm 14, 2023 Toán học 2 Comments 0 views

Toán Lớp 6: S = 2 + $2^{2}$ + $2^{3}$ + $2^{4}$ + … + $2^{98}$ + $2^{99}$ + $2^{100}$

Comments ( 2 )

lanthuhoa
14 Tháng Năm, 2023 at 6:59 chiều

Reply

S=2+2^2+2^3+2^4+…+2^98+2^99+2^100

2S=2^2+2^3+2^4+2^4+2^5+…+2^99+2^100+2^101

2S-S=(2^2+2^3+2^4+2^4+2^5+…+2^99+2^100+2^101)-(2^2+2^3+2^4+2^4+2^5+…+2^99+2^100+2^101)

S=2^101-2

#LHuy

$@Tr$
phuongthuydung
14 Tháng Năm, 2023 at 6:58 chiều

Reply

S = 2 + 2^2 + 2^3 + 2^4 + … + 2^98 + 2^99 + 2^100

=> 2S = 2^2 + 2^3 + 2^4 + 2^5 + … + 2^99 + 2^100 + 2^101

=> 2S – S = ( 2^2 + 2^3 + 2^4 + 2^5 + … + 2^99 + 2^100 + 2^101 ) – ( 2 + 2^2 + 2^3 + 2^4 + … + 2^98 + 2^99 + 2^100 )

=> S = 2^101 – 2

Vậy S = 2^101 – 2

#dtkc

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