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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Rút gọn S S=1+3+3^2+3^3+…+3^1001

Toán Lớp 6: Rút gọn S
S=1+3+3^2+3^3+…+3^1001

Comments ( 2 )

  1. Giải đáp:
     S=[3^1002-1]/2
    Lời giải và giải thích chi tiết:
    Theo bài ra ta có:
    S=1+3+3^2+3^3+…+3^1001
    =>3S=(1.3)+(3.3)+(3^2. 3)+…+(3^1001. 3)
    =>3S=3. 3^2+3^3+…+3^1002
    =>3S-S=(3. 3^2+3^3+…+3^1002)-(1+3+3^2+3^3+…+3^1001)
    =>2S=3^1002-1
    =>S=[3^1002-1]/2
    Vậy S=[3^1002-1]/2

  2. S=1+3+3^2+3^3+…+3^1001
    => 3S = 3 + 3^2 +3^3 + 3^4 + … +3^1002
    => 3S – S = ( 3 + 3^2 +3^3 + 3^4 + … +3^1002) -(1+3+3^2+3^3+…+3^1001)
    => 2S = 3^1002 -1
    => S = {3^1002-1}/2 
    Vậy S = {3^1002-1}/2 

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222-9+11+12:2*14+14 = ? ( )