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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: (n-8) chia hết (n+2) tìm n thuộc n

Toán Lớp 6: (n-8) chia hết (n+2) tìm n thuộc n

Comments ( 2 )

  1. (n – 8) \vdots (n + 2)
    => (n + 2) \vdots (n + 2)
    => (n + 2) + (n – 8) \vdots (n + 2)
    => 10 \vdots (m + 2)
    => (n + 2) ∈ Ư(10) = {1;2;5;10}
    => n ∈ {-1;0;3;8}
    Mà n ∈ N
    => n ∈ {0;3;8}
    Vậy n ∈ {0;3;8}

  2. n – 8 \vdots n + 2
    n + 2 \vdots n + 2
    => [(n + 2) – (n – 8)] \vdots n + 2
    => 10 \vdots n + 2
    => n + 2 in Ư(10)
    Ư(10) = {1; 2; 5; 10}
    => n + 2 in {1; 2; 5; 10}
    => n in {-1; 0; 3; 8}
    n in N
    => n in {0; 3; 8}
    Vậy n in {0; 3; 8}

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222-9+11+12:2*14+14 = ? ( )