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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Giải hộ bài này: Tìm số tự nhiên x biết rằng: 1/3+1/6+1/10+…+2/x(x+1)=2007/2009

Toán Lớp 6: Giải hộ bài này:
Tìm số tự nhiên x biết rằng:
1/3+1/6+1/10+…+2/x(x+1)=2007/2009

Comments ( 2 )

  1. 1/3 + 1/6 + 1/10 + …. + 2/(x . (x+1)) = 2007/2009
    => 2 . [1/6 + 1/12 + 1/20 + … + 1/(x.(x+1)) ] = 2007/2009
    => 2 . [ 1/(2.3) + 1/(3.4) + 1/(4.5) + …  + 1/(x.(x+1))] = 2007/2009
    => 2 . [1/2 – 1/3 + 1/3 – 1/4 + 1/4 – 1/5 + … + 1/x – 1/(x+1) ] = 2007/2009
    => 2 . (1/2 – 1/(x+1)) = 2007/2009
    => 1/2 – 1/(x+1) = 2007/4018
    => 1/(x+1) = 1/2009
    => x + 1 = 2009
    => x = 2008
    Vậy x =2008
     

  2. Giải đáp + Giải thích các bước giải:
    1/3+1/6+1/10+…+2/(x(x+1))=2007/2009
    =>2/6+2/12+2/20+…+2/(x(x+1))=2007/2009
    =>2/2.3+2/3.4+2/4.5+…+2/(x(x+1))=2007/2009
    =>2(1/2.3+1/3.4+1/4.5+…+1/(x(x+1))=2007/2009
    =>1/2-1/3+1/3-1/4+1/4-1/5+…+1/x-1/(x+1)=2007/2009:2
    =>1/2-1/(x+1)=2007/2009. 1/2
    =>1/2-1/(x+1)=2007/4018
    =>1/(x+1)=1/2-2007/4018
    =>1/(x+1)=2009/4018-2007/4018
    =>1/(x+1)=1/2009
    =>x+1=2009
    =>x=2009-1=2008

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222-9+11+12:2*14+14 = ? ( )