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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: E=[(2/193-3/386)×193/17+33/34]÷[(7/2001+11/4002)×2001/25+9/2]

Tháng Hai 7, 2023 Toán học 2 Comments 0 views

Toán Lớp 6: E=[(2/193-3/386)×193/17+33/34]÷[(7/2001+11/4002)×2001/25+9/2]

Comments ( 2 )

  1. annhocbichchaubich
    annhocbichchaubich
    7 Tháng Hai, 2023 at 1:17 sáng
    Reply
    E = [(2/193 – 3/386) xx 193/17 + 33/34] : [(7/2001 + 11/4002) xx 2001/25+ 9/2]
      = [ 1/386 xx 193/17 + 33/34] : [ 25/4002 xx 2001/25 + 9/2]
    =[1/34 + 33/34] : [1/2 + 9/2]
    = 34/34 : 10/2
    = 1 : 5
    = 1/5
    ⇒ E = 1/5

  2. dongoctuan
    dongoctuan
    7 Tháng Hai, 2023 at 1:17 sáng
    Reply
    E = [ ( 2/193 – 3/386 ) . 193/17 + 33/34 ] : [ ( 7/2001 + 11/4002 ) . 2001/25 + 9/2 ]
    E = [ ( 4/386 – 3/386 ) . 193/17 + 33/34 ] : [ ( 14/4002 + 11/4002 ) . 2001/25 + 9/2 ]
    E = [ 1/386 . 193/17 + 33/34 ] : [ 25/4002 . 2001/25 + 9/2 ]
    E = [ 1/34 + 33/34 ] : [ 1/2 + 9/2 ]
    E = 1 : 5
    E = 1/5
    Vậy , E = 1/5 .

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222-9+11+12:2*14+14 = ? ( )

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