Toán Lớp 6: chứng minh rằng A=2 + mũ 2 +2 mũ 3+ 2 mũ 4 +… + 2 mũ 100 chia hết cho 6
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Toán Lớp 6: chứng minh rằng A=2 + mũ 2 +2 mũ 3+ 2 mũ 4 +… + 2 mũ 100 chia hết cho 6
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$<=>A= (2+2^2)+(2^3+2^4)+…+(2^{99}+2^{100})$
$<=>A= (2+2^2)+2^2(2+2^2)+…+2^{98}.(2+2^2)$
$<=>A= (2+2^2)(1+2^2+..+2^{98})$
$<=>A= 6.(1+2^2+..+2^{98})$ chia hết cho $6$