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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Cho a/b = c/d. Chứng tỏ rằng : (b-3a)/a = (d-3c)/c

Toán Lớp 6: Cho a/b = c/d. Chứng tỏ rằng :
(b-3a)/a = (d-3c)/c

Comments ( 2 )

  1. Ta có : 
    $\frac{a}{b}$ = $\frac{c}{d}$ 
    => $\frac{b}{a}$ = $\frac{d}{c}$
    =>  $\frac{b}{a}$ – 3 = $\frac{d}{c}$ – 3
    => $\frac{b}{a}$ – $\frac{3a}{a}$ = $\frac{d}{c}$ – $\frac{3c}{c}$
    => $\frac{b-3a}{a}$  = $\frac{d-3c}{c}$
    Vậy ….

  2. Giải đáp:
    $\\$
    Đặt a/b=c/d=k (k \ne 0)
    -> $\begin{cases} \dfrac{a}{b}=k\\ \dfrac{c}{d}=k \end{cases}$ -> $\begin{cases} a=bk\\c=dk \end{cases}$
    Có : (b-3a)/a
    = (b – 3bk)/(bk)
    = (b (1 – 3k) )/(bk)
    = (1-3k)/k (1)
    Có : (d-3c)/c
    = (d-3dk)/(dk)
    = (d (1-3k) )/(dk)
    = (1-3k)/k (2)
    Từ (1), (2)
    -> (b-3a)/a = (d-3c)/c (= (1-3k)/k)
    -> đpcm
     

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222-9+11+12:2*14+14 = ? ( )

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