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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Cho A = 1+3+3^2+3^3 +… 3^11 Chứng minh rằng : a, a : 13 b, a : 40

Toán Lớp 6: Cho A = 1+3+3^2+3^3 +… 3^11
Chứng minh rằng :
a, a : 13
b, a : 40

Comments ( 2 )

  1. A=1+3+3^2+3^3 +…+3^11

    A=(1+3+3^2)+(3^3+3^4+3^5)+…….+(3^9+3^10+3^11)

    A=1(1+3+3^2)+3^3(1+3+3^2)+…….+3^9+(1+3+3^2)

    A=1.13+3^3. 13+……+3^9. 13

    A=13.(1+3^3+….+3^9)

    Vì 13vdots13

    =>A vdots 13

    A=1+3+3^2+3^3 +… 3^11

    A=( 1 + 3 + 3^2 + 3^3 ) +…+( 3^8 + 3^9 + 3^10 + 3^11 )

    A=1(1+3+3^2+3^3)+3^4(1+3+3^2+3^3)+3^8(1+3+3^2+3^3)

    A=1.40+3^4. 40+3^8. 40

    A=40.(1+3^4+3^8)

    Vì 40vdots40

    =>A vdots 40

     

  2. C = ( 1 + 3 + $3^{2}$ ) + ( $3^{3}$ + $3^{4}$ + $3^{5}$ )+…+( $3^{9}$ + $3^{10}$ + $3^{11}$ )
    C = 13 . 1 + $3^{3}$ . 13 +…+ $3^{9}$ . 13
    C = 13 . ( 1 + $3^{3}$  + $3^{6}$ + $3^{9}$ )
    Chia hết cho 13 .
    C = ( 1 + 3 + $3^{2}$ + $3^{3}$ ) +…+( $3^{8}$ + $3^{9}$ + $3^{10}$ + $3^{11}$ )
    C = 40 . 1 + 40 . $3^{4}$ + 40 . $3^{8}$ 
    C = 40 . ( 1 . $3^{4}$ + $3^{8}$ )
    Chia hết cho 40 .
      

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222-9+11+12:2*14+14 = ? ( )

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