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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Cho a=1+3+3<2+3<3+...+3<101 Chứng minh rằng a chia hết cho 13

Toán Lớp 6: Cho a=1+3+3<2+3<3+...+3<101 Chứng minh rằng a chia hết cho 13

Comments ( 2 )

  1. A = 1 + 3 + 3^2 + 3^3 + … + 3^101
    A = (1 + 3 + 3^2) + (3^3 + 3^4 + 3^5) + … + (3^99 + 3^100 + 3^101)
    A = 1.(1 + 3 + 3^2) + 3^3 . (1 + 3 + 3^2) + … + 3^99 . (1 + 3 + 3^2)
    A = 1 . 13 + 3^3 . 13 + … + 3^99 . 13
    A = (1 + 3^3 + 3^99) . 13 \vdots 13  (đpcm)
    Vậy A \vdots 13

  2. Lời giải chi tiết:
    A=1+3+3^2+3^3+…+3^101
    A=(1+3+3^2)+(3^3+3^4+3^5)+…+(3^99+3^100+3^101)
    A=1.(1+3+3^2)+3^3.(1+3+3^2)+…+3^99.(1+3+3^2)
    A=1.13+3^(3).13+…+3^(99).13
    A=13.(1+3^3+…+3^99)\vdots13
    Vậy A\vdots13

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222-9+11+12:2*14+14 = ? ( )

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