Toán Lớp 6: bài 1.1213-[1250-(4^2.3)^3.4] bài 2.tìm x:(25-2x)^3:5-3^2=4^2
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Toán Lớp 6: bài 1.1213-[1250-(4^2.3)^3.4] bài 2.tìm x:(25-2x)^3:5-3^2=4^2
Comments ( 2 )
Giải đáp và lời giải
bb\text{Bài 1.
1213-[1250-(4^(2).3)^(3).4]
=1213-[1250-(16.3)^(3).4]
=1213-(1250-48^(3).4)
=1213-(1250-110592.4)
=1213-(1250-442368)
=1213-(-441118)
=442331
bb\text{Bài 2.
(25-2x)^3:5-3^2=4^2
=>(25-2x)^3:5=4^2+3^2
=>(25-2x)^3:5=25
=>(25-2x)^3=25.5
=>(25-2x)^3=5^3
=>25-2x=5
=>2x=25-5
=>2x=20
=>x=20:2
=>x=10
Vậy x=10
Bài 1:
1213 – [1250 – (4^{2} . 3)^{3} . 4]
=1213 – [1250 – (16 . 3)^{3} . 4]
=1213 – [1250 – 48^{3} . 4]
=1213 – [1250 – 110592 . 4]
=1213 – [1250 – 442368]
=1213 – (-44118)
=442331
Bài 2:
(25 – 2x)^{3} : 5 – 3^{2} = 4^{2}
<=>(25 – 2x)^{3} : 5 = 16 + 9
<=>(25 – 2x)^{3} : 5 = 25
<=>(25 – 2x)^{3} = 25 . 5
<=>(25 – 2x)^{3} = 125 = 5^{3}
<=>25 – 2x = 5
<=>2x = 25 – 5
<=>2x = 20
<=>x = 20 : 2
<=>x = 10
Vậy x = 10