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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: b) 2 x [(7- 3 mũ 3 : 3 mũ 2 ) : 2 mũ 2 + 99] -100 c) 3 mũ 2 x [(5 mũ 2 – 3) : 11] – 2 mũ 4 + 2 x 10 mũ 3 Nhanh nha mik cần gấp

Toán Lớp 6: b) 2 x [(7- 3 mũ 3 : 3 mũ 2 ) : 2 mũ 2 + 99] -100
c) 3 mũ 2 x [(5 mũ 2 – 3) : 11] – 2 mũ 4 + 2 x 10 mũ 3
Nhanh nha mik cần gấp

Comments ( 2 )

  1. b) 2 × [ ( 7 – 3^3 : 3^2 ) : 2^2 + 99 ] – 100
    = 2 × [ ( 7 – 3 ) : 4 + 99 ] – 100
    = 2 × ( 4 : 4 + 99 ) – 100
    = 2 × ( 1 + 99 ) – 100
    = 2 × 100 – 100
    = 200 – 100 = 100
                                                                  
    c) 3^2 × [( 5^2 – 3 ) : 11 ] – 2^4 + 2 × 10^3
    = 9 × [( 25 – 3 ) : 11 ] – 16 + 2 × 1000
    = 9 × ( 22 : 11 ) – 16 + 2000
    = 9 × 2 – 16 + 2000
    = 18 – 16 + 2000
    = 2 + 2000 = 2002
    @ Rin

  2. $#$nguyenanh$99999^{}$
    Giải đáp : b = $100^{}$,  c = $2002^{}$
    Lời giải và giải thích chi tiết:
    b)
    $2^{}$ x [($7^{}$- $3^{3}$  : $3^{2}$ ) : $2^{2}$ + $99^{}$] – $100^{}$
    = $2^{}$ x [($7^{}$ – $3^{}$ ) : $2^{2}$ + $99^{}$] – $100^{}$
    = $2^{}$ x [ $4^{}$ : $2^{2}$ + $99^{}$] – $100^{}$
    = $2^{}$ x [$1^{}$ + $99^{}$] – $100^{}$
    = $200^{}$ -$100^{}$ = $100^{}$
    c)
    $3^{2}$  x [($5^{2}$  – $3^{}$ ) : $11^{}$ ] – $2^{4}$  + $2^{}$  x $10^{3}$ 
    = $9^{}$   x [$22^{}$ : $11^{}$] – $16^{}$  + $2^{}$ x $10^{3}$ 
    = $9^{}$ x $2^{}$ – $16^{}$  + $2^{}$ x $1000^{}$
    = $18^{}$ – $16^{}$+ $2000^{}$
    = $2^{}$ + $2000^{}$
    = $2002^{}$
    Chúc bạn học tốt (^__^)
     

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222-9+11+12:2*14+14 = ? ( )

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