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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: A=3+3^2+3^3+3^4+3^5+3^6+3^7+3^8+3^9+3^10 chứng tỏ rằng A chai hết cho12

Toán Lớp 6: A=3+3^2+3^3+3^4+3^5+3^6+3^7+3^8+3^9+3^10 chứng tỏ rằng A chai hết cho12

Comments ( 2 )

  1. Giải đáp:
     
    Lời giải và giải thích chi tiết:
     Ta có :
      $A=3+3^{2}+3^{3}+3^{4}+…+3^{9}+33^{10}$
        $=(3+3^{2})+(3^{3}+3^{4})+…+(3^{9}+33^{10})$ 
        $=(3+3^{2})+3^{2}(3+3^{2})+…+3^{8}(3+3^{2})$
        $=(3+9)+3^{2}(3+9)+…+3^{8}(3+9)$
        $=12+3^{2}.12+…+3^{8}.12$
        $=12.(1+3^{2}+…+3^{8})$   luôn chia hết cho 12
    => A chia hết cho 12

  2. A=3+3^2+3^3+3^4+3^5+3^6+3^7+3^8+3^9+3^10
    A=(3+3^2)+(3^3+3^4)+(3^5+3^6)+(3^7+3^8)+(3^9+3^10)
    A=1.(3+3^2)+3^2.(3+3^2)+3^4.(3+3^2)+3^6.(3+3^2)+3^8.(3+3^2)
    A=1.12+3^2. 12+3^4. 12+3^6. 12+3^8. 12
    A=12.(1+3^2+3^4+3^6+3^8)
    Vì 12vdots12
    =>Avdots12

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222-9+11+12:2*14+14 = ? ( )

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