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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: a. 10+5.x=5^5:5^3 + -10 b. ( x-2 ) +( -12 ) = ( -58 ) c. ( x-1)^2 – ( -12 ) = 37

Toán Lớp 6: a. 10+5.x=5^5:5^3 + -10
b. ( x-2 ) +( -12 ) = ( -58 )
c. ( x-1)^2 – ( -12 ) = 37

Comments ( 2 )

  1. a)
    10 + 5x = 5^5 : 5^3 + (-10)
    => 10 + 5x = 5^2 – 10
    => 10 +5x = 25 – 10
    => 10 + 5x = 15
    => 5x = 15-10
    =>5x=5
    =>x=5:5
    =>x=1
    Vậy x=1
    b)
    (x-2) + (-12) = (-58)
    => x – 2 – 12 = -58
    => x = -58 + 2 + 12
    => x=  -44
    Vậy x=-44
    c)
    (x-1)^2  – (-12) = 37
    => (x-1)^2 + 12 = 37
    => (x-1)^2 = 37 -12
    => (x-1)^2=  25
    => (x-1)^2 = (+-5)^2
    =>x-1=5 hoặc x-1=-5
    +)x-1=5=>x=6
    +)x-1=-5=>x=-4
    Vậy x \in {6;-4}
     

  2. a)10+5x=5^5 :5^3 +(-10)
    =>10+5x=5^(5-3)-10
    =>10+5x=5^2 -10
    =>10+5x=25-10
    =>10+5x=15
    =>5x=15-10
    =>5x=5
    =>x=1
    Vậy x=1
    b)(x-2)+(-12)=(-58)
    =>x-2=(-58)-(-12)
    =>x-2=-46
    =>x=-46+2
    =>x=-44
    Vậy x=-44
    c)(x-1)²-(-12)=37
    =>(x-1)²+12=37
    =>(x-1)²=25
    =>x-1=(+-5)²
    => \(\left[ \begin{array}{l}x-1=5\\x-1=-5\end{array} \right.\) 
    => \(\left[ \begin{array}{l}x=6\\x=-4\end{array} \right.\) 
    Vậy x=6 hoặc x=-4

     

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222-9+11+12:2*14+14 = ? ( )

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