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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: a \[ x-1] ^2=1 b \7^2x-6 = 49 c\ [ 2x-16]^7 = 128 d\ [3.[x+2]:7]ư.4=120 e\ x[x-1]=0 f \ x^3 .x^2 =2^8 : 2^

Toán Lớp 6: a \[ x-1] ^2=1 b \7^2x-6 = 49 c\ [ 2x-16]^7 = 128 d\ [3.[x+2]:7]ư.4=120 e\ x[x-1]=0
f \ x^3 .x^2 =2^8 : 2^3

Comments ( 1 )

  1. Lời giải chi tiết:
    a) (x-1)^2=1
    =>\(\left[ \begin{array}{l}x-1=1\\x-1=-1\end{array} \right.\)
    =>\(\left[ \begin{array}{l}x=2\\x=0\end{array} \right.\)
    Vậy x=2 hoặc x=0
    b) 7^(2x-6)=49
    =>7^(2x-6)=7^2
    =>2x-6=2
    =>2x=2+6
    =>2x=8
    =>x=8:2
    =>x=4
    Vậy x=4
    c) (2x-16)^7=128
    =>(2x-16)^7=2^7
    =>2x-16=2
    =>2x=2+16
    =>2x=18
    =>x=18:2
    =>x=9
    Vậy x=9
    d) [3.(x+2):7].4=120
    =>3.(x+2):7=120:4
    =>3.(x+2):7=30
    =>3.(x+2)=30.7
    =>3.(x+2)=210
    =>x+2=210:3
    =>x+2=70
    =>x=70-2
    =>x=68
    Vậy x=68
    e) x.(x-1)=0
    =>\(\left[ \begin{array}{l}x=0\\x-1=0\end{array} \right.\)
    =>\(\left[ \begin{array}{l}x=0\\x=1\end{array} \right.\)
    Vậy x=0 hoặc x=1
    f) x^(3).x^2=2^8:2^3
    =>x^(3+2)=2^(8-3)
    =>x^5=2^5
    =>x=2
    Vậy x=2
    @uniquetimehunter

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222-9+11+12:2*14+14 = ? ( )

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