Toán Lớp 6: 6: (x+1)
4x+2 =64
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Toán Lớp 6: 6: (x+1)
4x+2 =64
Giup mik với ạ
Comments ( 2 )
$*$ Ta có $:$ $6$ $\vdots$ $(x+1)$
$⇒$ $x+1$ $∈$ $Ư$ $(6)$
$⇒$ $x+1$ $∈$ { $-6$ $;$ $-3$ $;$ $-2$ $;$ $-1$ $;$ $1$ $;$ $2$ $;$ $3$ $;$ $6$ }
$⇒$ $x$ $∈$ { $-7$ $;$ $-4$ $;$ $-3$ $;$ $-2$ $;$ $0$ $;$ $1$ $;$ $2$ $;$ $5$ }
$*$ $4x$ $+$ $2$ $=$ $64$
$⇒$ $4x$ $=$ $64$ $-$ $2$
$⇒$ $4x$ $=$ $62$
$⇒$ $x$ $=$ $62$ $:$ $4$ $=$ $15,5$
Vậy $x$ $=$ $15,5$
6vdots(x+1)
=>x+1in Ư(6)
=>x+1in{+-1;+-2;+-3;+-6}
=>x in{0;-2;1;-3;2;-4;5;-7}
Vậy x in{0;-2;1;-3;2;-4;5;-7}
4x+2=64
4x=64-2
4x=62
x=62:4
x=31/2
Vậy x=31/2
@Ki ng