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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 5: 1/3*5 + 1/5*7+1/7*9+…+1/x*(x+2)=103/600

Toán Lớp 5: 1/3*5 + 1/5*7+1/7*9+…+1/x*(x+2)=103/600

Comments ( 2 )

  1. 1/(3xx5) + 1/(5 xx 7) + 1/( 7 xx9) + …. + 1/( x xx ( x + 2)) = 103/600
    1/2 xx ( 2/(3xx5) + 2/(5 xx 7) + 2/( 7 xx9) + …. + 2/( x xx ( x + 2))) = 103/600
    1/2 xx ( 1/3 – 1/5 + 1/5 – 1/7 + 1/7 – 1/9 + … + 1/x – 1/(x+2)) = 103/600
    1/2 xx ( 1/3 – 1/( x+2)) = 103/600
    1/3 – 1/(x + 2) = 103/600 : 1/2
    1/3 – 1/(x+2) = 103/300
    1/(x+2) = 1/3 – 103/300
    Mà 103/300 > 1/3
    ⇒ x không tồn tại

  2. 1/(3xx5) + 1/(5 xx 7) + 1/( 7 xx9) + …. + 1/( x xx ( x + 2)) = 103/600
    1/2 xx ( 2/(3xx5) + 2/(5 xx 7) + 2/( 7 xx 9 ) + …. + 2/( x xx ( x + 2 ) ) )= 103/600
    1/2 xx ( 1/3 – 1/5 + 1/5 – 1/7 + 1/7 – 1/9 + … + 1/x – 1/(x+2)) = 103/600
    1/3 – 1/( x+2) = 103/600 : 1/2
    1/3 – 1/(x + 2) = 103/300
    1/(x+2) = 1/3 – 103/300
    Vì 103/300 > 1/3 nên x không tồn tại
    Vậy , x không tồn tại .

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222-9+11+12:2*14+14 = ? ( )

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