Toán Lớp 12: Tìm nguyên hàm của fx=(2x+3)^2
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Toán Lớp 12: Tìm nguyên hàm của fx=(2x+3)^2
Comments ( 1 )
* Đặt: 2x+3=t ->2dx=dt ->dx=(dt)/2
*
$\displaystyle\int_{}^{} { (2x+3)^2} dx$
$=$$\displaystyle\int_{}^{} { t^2}\dfrac{dt}{2}$
=1/2$\displaystyle\int_{}^{} { t^2} dt$
=1/2. t^3/3+C=t^3/6+C
=(2x+3)^3/6+C