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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: sin^4(x/8)+cos^4(x/8)=2m-1 tìm m để pt có nghiệm trong khoảng (0;pi)

Toán Lớp 11: sin^4(x/8)+cos^4(x/8)=2m-1
tìm m để pt có nghiệm trong khoảng (0;pi)

Comments ( 1 )

  1. $\begin{array}{l} x \in \left( {0;\pi } \right) \Rightarrow \dfrac{x}{4} \in \left( {0;\dfrac{\pi }{4}} \right)\\  \Rightarrow 0 \le \sin \left( {\dfrac{x}{4}} \right) \le \dfrac{{\sqrt 2 }}{2} \Rightarrow 0 \le {\sin ^2}\left( {\dfrac{x}{4}} \right) \le \dfrac{1}{2}\\ \left[ {{{\sin }^4}\left( {\dfrac{x}{8}} \right) + {{\cos }^4}\left( {\dfrac{x}{8}} \right)} \right] = 2m – 1\\  \Leftrightarrow {\left[ {{{\sin }^2}\left( {\dfrac{x}{8}} \right) + {{\cos }^2}\left( {\dfrac{x}{8}} \right)} \right]^2} – 2{\sin ^2}\left( {\dfrac{x}{8}} \right){\cos ^2}\left( {\dfrac{x}{8}} \right) = 2m – 1\\  \Leftrightarrow 1 – \dfrac{1}{2}{\sin ^2}\left( {\dfrac{x}{4}} \right) = 2m – 1\\  \Leftrightarrow \dfrac{1}{2}{\sin ^2}\left( {\dfrac{x}{4}} \right) = 2 – 2m\\  \Leftrightarrow {\sin ^2}\left( {\dfrac{x}{4}} \right) = 4 – 4m\\ \text{Phương trình có nghiệm} \Leftrightarrow 0 \le 4 – 4m \le \dfrac{1}{2}\\  \Leftrightarrow \dfrac{7}{8} \le m \le 1 \end{array}$  

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222-9+11+12:2*14+14 = ? ( )

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