Register Now

Login

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: phương trình (sinx +1)(2 cos 2x -√2)=0 có nghiệm là ?

Toán Lớp 11: phương trình (sinx +1)(2 cos 2x -√2)=0 có nghiệm là ?

Comments ( 1 )

  1. Giải đáp:
    \( S = \left\{- \dfrac{\pi}{2} + k2\pi;\ – \dfrac{\pi}{8} + k\pi;\ \dfrac{\pi}{8} + k\pi\ \Bigg|\ k\in\Bbb Z\right\}\)
    Lời giải và giải thích chi tiết:
    \(\begin{array}{l}
    \quad (\sin x + 1)\left(2\cos2x – \sqrt2\right) =0\\
    \Leftrightarrow \left[\begin{array}{l}\sin x = -1\\\cos2x= \dfrac{\sqrt2}{2}\end{array}\right.\\
    \Leftrightarrow \left[\begin{array}{l}x = – \dfrac{\pi}{2} + k2\pi\\2x = – \dfrac{\pi}{4} + k2\pi\\2x = \dfrac{\pi}{4} + k2\pi\end{array}\right.\\
    \Leftrightarrow \left[\begin{array}{l}x = – \dfrac{\pi}{2} + k2\pi\\x = – \dfrac{\pi}{8} + k\pi\\x = \dfrac{\pi}{8} + k\pi\end{array}\right.\quad (k\in\Bbb Z)\\
    \text{Vậy}\ S = \left\{- \dfrac{\pi}{2} + k2\pi;\ – \dfrac{\pi}{8} + k\pi;\ \dfrac{\pi}{8} + k\pi\ \Bigg|\ k\in\Bbb Z\right\}
    \end{array}\)

Leave a reply

222-9+11+12:2*14+14 = ? ( )