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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: Giúp em với ạ tan ( x – 15• ) = 1/√3

Toán Lớp 11: Giúp em với ạ
tan ( x – 15• ) = 1/√3

Comments ( 2 )

  1. Giải đáp: x=45^{o}+k180^o \ (k∈\mathbb{Z})
    Giải:
    Đkxđ:
    cos(x-15^o) \ne 0
    ⇔ x-15^o \ne 90^{o}+k180^o
    ⇔ x \ne 105^{o}+k180^o
    Ta có:
    tan(x-15^o)=\frac{1}{\sqrt{3}}
    ⇔ tan(x-15^o)=tan30^o
    ⇔ x-15^o=30^{o}+k180^o
    ⇔ x=45^{o}+k180^o \ (k∈\mathbb{Z}) (thỏa)
    Vậy x=45^{o}+k180^o \ (k∈\mathbb{Z})

  2. $tan (x-15^o)=\dfrac{1}{\sqrt[]{3}}$
    $⇔tan(x-15^o)=tan30^o$
    $⇔x-15^o=30^o+k180^o$
    $⇔x=45^o+k180^o(k∈Z)$

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222-9+11+12:2*14+14 = ? ( )

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