Toán Lớp 11: giải phương trình: sin(3x+1) =1/2
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Toán Lớp 11: giải phương trình: sin(3x+1) =1/2
Comments ( 2 )
<=> [{:(3 x + 1 = ( 5pi )/6 + k 2 pi ),(3 x + 1 = ( pi )/6 + k 2 pi ):}:} (kinZZ)
<=> [{:(3 x = ( 5pi )/6 + k 2 pi – 1),(3 x = ( pi )/6 + k 2 pi – 1):}:} (kinZZ)
<=> [{:( x = ( 5pi )/(18) + ( k 2 pi )/3 – 1/3),( x = ( pi )/(18) + ( k 2 pi )/3 – 1/3):}:} (kinZZ)
Sin(3x+1)=1/2
<=>sin(3x+1)=sinπ/6
<=>3x+1=π/6+k2π
3x+1=π-π/6+k2π
<=>3x=π/6-1+k2π
3x=5π/6-1+k2π
<=>x=π/18-1/3+k2π/3
x=5π/18-1/3+k2π/3