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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: Giải phương trình sau 5sinx-1=0

Toán Lớp 11: Giải phương trình sau
5sinx-1=0

Comments ( 2 )

  1. ~rai~
    \(5\sin x-1=0\\\Leftrightarrow \sin x=\dfrac{1}{5}\\\Leftrightarrow \left[\begin{array}{I}x=\arcsin\dfrac{1}{5}+k2\pi\\x=\pi-\arcsin\dfrac{1}{5}+k2\pi.\end{array}\right.\quad(k\in\mathbb{Z})\\\text{Vậy S=}\left\{\arcsin\dfrac{1}{5}+k2\pi;\pi-\arcsin\dfrac{1}{5}+k2\pi\Big|k\in\mathbb{Z}\right\}.\)

  2. Giải đáp:
    \(S = \left\{\arcsin\left(\dfrac15\right) + k2\pi;\ \pi – \arcsin\left(\dfrac15\right) + k2\pi\ \Bigg|\ k\in\Bbb Z\right\}\) 
    Lời giải và giải thích chi tiết:
    \(\begin{array}{l}
    \quad 5\sin x – 1 = 0\\
    \Leftrightarrow \sin x = \dfrac15\\
    \Leftrightarrow \left[\begin{array}{l}x = \arcsin\left(\dfrac15\right) + k2\pi\\x = \pi – \arcsin\left(\dfrac15\right) + k2\pi\end{array}\right.\quad (k\in\Bbb Z)\\
    \text{Vậy}\ S = \left\{\arcsin\left(\dfrac15\right) + k2\pi;\ \pi – \arcsin\left(\dfrac15\right) + k2\pi\ \Bigg|\ k\in\Bbb Z\right\}
    \end{array}\) 

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222-9+11+12:2*14+14 = ? ( )