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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 10: Rút gọn x+√x/√x+x-1/√x+1-x-4/√x-2 Giúp minh vs.

Toán Lớp 10: Rút gọn
x+√x/√x+x-1/√x+1-x-4/√x-2
Giúp minh vs.

Comments ( 2 )

  1. Giải đáp:
    $\begin{array}{l}
    \dfrac{{x + \sqrt x }}{{\sqrt x }} + \dfrac{{x – 1}}{{\sqrt x  + 1}} – \dfrac{{x – 4}}{{\sqrt x  – 2}}\\
     = \dfrac{{\sqrt x \left( {\sqrt x  + 1} \right)}}{{\sqrt x }} + \dfrac{{\left( {\sqrt x  + 1} \right)\left( {\sqrt x  – 1} \right)}}{{\sqrt x  + 1}} – \dfrac{{\left( {\sqrt x  – 2} \right)\left( {\sqrt x  + 2} \right)}}{{\sqrt x  – 2}}\\
     = \sqrt x  + 1 + \sqrt x  – 1 – \left( {\sqrt x  + 2} \right)\\
     = 2\sqrt x  – \sqrt x  – 2\\
     = \sqrt x  – 2
    \end{array}$

  2. #tnvt
    \frac{x+\sqrt{x}}{\sqrt{x}}+\frac{x-1}{\sqrt{x}+1}-\frac{x-4}{\sqrt{x}-2}(x\ne4,x>0)
    =\frac{\sqrt{x}(\sqrt{x}+1)}{\sqrt{x}}+\frac{(\sqrt{x}-1)(\sqrt{x}+1)}{\sqrt{x}+1}-\frac{(\sqrt{x}-2)(\sqrt{x}+2)}{\sqrt{x}-2}
    =\sqrt{x}+1+\sqrt{x}-1-(\sqrt{x}+2)
    =2\sqrt{x}-\sqrt{x}-2
    =\sqrt{x}-2

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222-9+11+12:2*14+14 = ? ( )