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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 10: Giải pt $\sqrt[]{x^2+3}$ = $\sqrt[]{x+3}$ + 3$x^{2}$ -3

Toán Lớp 10: Giải pt
$\sqrt[]{x^2+3}$ = $\sqrt[]{x+3}$ + 3$x^{2}$ -3

Comments ( 2 )

  1. Bạn tham khảo:
    sqrt(x^2+3)=sqrt(x+3)+3x^2-3
    ĐK: x+3>=3 ⇔ x>=-3
    ⇔-3x^2-(sqrtx+3)+sqrt(x^2+3)+3=0
    ⇔(x-1)^2(81x^6+162x^5-99x^4-378x^3-242x^2-72x-27)=0
    ⇔(x-1)^2=0
    ⇔x-1=0
    ⇔x=1
     

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222-9+11+12:2*14+14 = ? ( )