Toán Lớp 10: giải PT √x² – 5x + 1 = x
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Toán Lớp 10: giải PT √x² – 5x + 1 = x
Comments ( 1 )
\quad \sqrt{x^2 -5x}+ 1 =x\\\Leftrightarrow \sqrt{x^2 – 5x} = x-1\\
\Leftrightarrow \begin{cases}x-1 \geqslant 0\\x^2 – 5x = x^2 -2x + 1\end{cases}\\
\Leftrightarrow \begin{cases}x \geqslant 1\\3x = -1\end{cases}\\\Leftrightarrow \begin{cases}x \geqslant 1\\x = -\dfrac13\end{cases}\\
\Leftrightarrow x\in\varnothing\\
\text{Vậy}\ S = \varnothing
\end{array}\)