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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 10: G = { x ∈ Z|(x ² – 3x + 2)(x ² – √3x) = 0 Liệt kê các phần tử sau

Toán Lớp 10: G = { x ∈ Z|(x ² – 3x + 2)(x ² – √3x) = 0
Liệt kê các phần tử sau

Comments ( 1 )

  1. G={x\in ZZ|(x^2-3x+2)(x^2-\sqrt{3}x)=0}
    Ta có: (x^2-3x+2)(x^2-\sqrt{3}x)=0
    <=>x(x-\sqrt3)(x-1)(x-2)=0
    <=>\(\left[ \begin{array}{l}\ \ \ \ x=0\\x-\sqrt3=0\\\ \ x-1=0\\ \ \ x-2=0\end{array} \right.\) <=>\(\left[ \begin{array}{l}\ x=0\\x=\sqrt3\\\ x=1\\\ x=2\end{array} \right.\) 
    Mà x\in ZZ nên G={0;1;2}
     

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222-9+11+12:2*14+14 = ? ( )

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