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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 10: $a)\sqrt[]{3-x}=3x-5$ $b)\sqrt[]{5x-10}=8-x$ $c)\sqrt[]{x-1}=x-3$ giúp e vs ah

Home/ Toán Lớp 10: $a)\sqrt[]{3-x}=3x-5$ $b)\sqrt[]{5x-10}=8-x$ $c)\sqrt[]{x-1}=x-3$ giúp e vs ah

Toán Lớp 10: $a)\sqrt[]{3-x}=3x-5$ $b)\sqrt[]{5x-10}=8-x$ $c)\sqrt[]{x-1}=x-3$ giúp e vs ah

Tháng Năm 10, 2022 Toán học 1 Comment 0 views

Toán Lớp 10: $a)\sqrt[]{3-x}=3x-5$
$b)\sqrt[]{5x-10}=8-x$
$c)\sqrt[]{x-1}=x-3$
giúp e vs ah

Comments ( 1 )

  1. ngoclanquynh
    ngoclanquynh
    10 Tháng Năm, 2022 at 7:18 sáng
    Reply
    $\text{a) $\sqrt{3-x}$ = 3x – 5 }$
    $\Leftrightarrow$ $\left \{ {{3x-5\ge 0 } \atop {3-x = (3x-5)^{2}}} \right.$
    $\Leftrightarrow$ $\left \{ {{x=5/3} \atop {\left[ \begin{array}{l}x=2\\x=11/9\end{array} \right. }} \right.$
    $\text{b. $\sqrt{5x-10}$ = 8-x }$ 
    $\Leftrightarrow$ $\left \{ {{5x-10\ge 0 } \atop {5x-10 = (8-x)^{2}}} \right.$
    $\Leftrightarrow$$\left \{ {{x\ge 2} \atop {\left[ \begin{array}{l}x=\dfrac{21+\sqrt{145}}{2}\\x=\dfrac{21-\sqrt{145}}{2}\end{array} \right. }} \right.$
     $\text{c. $\sqrt{x-1}$ = x-3 }$
    $\Leftrightarrow$ $\left \{ {{x-3\ge 0 } \atop {x-1 = (x-3)^{2}}} \right.$
    $\Leftrightarrow$ $\left \{ {{x\ge 3} \atop {\left[ \begin{array}{l}x=5\\x=2\end{array} \right. }} \right.$
    $\text{Chúc bạn học tốt :33}$

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222-9+11+12:2*14+14 = ? ( )

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